Domain: x ≠ ±
π⁄2, ±
3π⁄2, ...
Range: ℝ
Period: π x-intercepts: x = 0, ±&pi, ±2π, ...
Asymptotes: x = ±π⁄2,
± 3π⁄2, ...
Domain: x ≠ 0, ±π, ±2π, ...
Range: ℝ
Period: π x-intercepts: x = ±π⁄2,
± 3π⁄2, ...
Asymptotes: x = 0, ±π, ±2π, ... Example 7.
Draw the graphs of y = a tan bx and y = a cot bx for a, b > 0.
Solution y = tan x → y = a tan bx,
(x, y) → (x⁄b,
ay)
y = cot x → y = a cot bx
(x, y) → (x⁄b,
ay)
Graph of y = sec x and y = csc x
Domain: x ≠ ±
π⁄2, ±
3π⁄2, ...
Range: y ≤ -1 or y ≥ 1
Period: 2π x-intercepts: x = 0, ±&pi, ±2π, ...
Asymptotes: x = ±π⁄2,
± 3π⁄2, ...
Domain: x ≠ 0, ±π, ±2π, ...
Range: y ≤ -1 or y ≥ 1
Period: 2π x-intercepts: x = ±π⁄2,
± 3π⁄2, ...
Asymptotes: x = 0, ±π, ±2π, ...
Note that transform y = sec x to y = a sec bxand y = csc x to y = a csc bx
with (x, y) → x⁄b, ay), we get the graph of
y = a csc bx and y = csc bx.
Exercise 7.3
1. Draw the graph of (a) y =
1⁄2 tan πx Solution
Domain: x ≠ ±
1⁄2, ±
3⁄2, ...
Range: ℝ
Period: 1 x-intercepts: x = 0, ±1, ±2, ...
Asymptotes: x = ±1⁄2,
± 3⁄2, ...
(b) y = 2 tan
1⁄2x.
Domain: x ≠ 0, ±π, ±3π, ±5π ...
Range: ℝ
Period: 2π x-intercepts: x = ±2π,
± 4π, ...
Asymptotes: x = 0, ±π, ±3π, 5π ...
2. Draw the graph of (a) y = 2 cot
π⁄3x
(b) y = 3 cot 2x. Solution
(a) y = 2 cot
π⁄3x
Domain x ≠ 0, ±3, ±6, ...
Range ℝ
Period 3 x-intercept ±3⁄2,
π9⁄2, ...
Asymptote x = 0, ±3, ±6, ...
(b) y = 3 cot 2x.
Domain x ≠ 0, ±π⁄2, ± π,
± 3π⁄2, ...
Range ℝ
Period π⁄2 x-intercepts ±π⁄4,
±3π⁄4, ...
Asymptotes x = 0, ±π⁄2,
±π, ±3π⁄2, ...
3. Draw the graph of (a) y = 2 sec πx Solution
(a) y = 2 sec πx
Domain x ≠ ±0.5, ±1.5, ±2.5, ...
Range y ≤ -2 of y ≥ 2
Period 2 x-intercepts ±1⁄2,
±3⁄2, ...
Asymptotes x = ±0.5, ±1.5, ±2.5, ...
(b) y = 2 csc 1⁄2x.
Domain x ≠ ±0, ±2π, ±4π, ±6π ...
Range y ≤ -2 of y ≥ 2
Period 4π x-intercept 0, 2π, 4π, ...
Asymptotes x = ±0, ±2π, ±4π, ±6π, ...
4. Show that y = a tan bx , y = a cot bx, and y = a csc bx are odd functions. Solution
Let y = f(x) = a tan bx f(-x) = a tan (b(-x))
= a tan (-bx)
= -a tan bx
= - f(x)
∴ y = a tan bx is an odd function.
Let y = g(x) = a cot bx g(-x) = a cot (b(-x))
= a cot (-bx)
= -a cot bx
= - g(x)
∴ y = a cot bx is an odd function.
Let y = h(x) = a cosec bx h(-x) = a cosec (b(-x))
= a cosec (-bx)
= -a cosec bx
= - h(x)
∴ y = a cosec bx is an odd function.
5. Show that y = a sec bx is an even function.
Solution
Let y = f(x) = a sec bx f(-x) = a sec (b(-x))
= a sec (-bx)
= a sec bx
= f(x)
∴ y = a sec bx is an even function.